k^2=145

Solution for k^2=145 equation:

k^2=145

We move all terms to the left:

k^2-(145)=0

a = 1; b = 0; c = -145;
Δ = b2-4ac
Δ = 02-4·1·(-145)
Δ = 580
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{580}=\sqrt{4*145}=\sqrt{4}*\sqrt{145}=2\sqrt{145}$
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2\sqrt{145}}{2*1}=\frac{0-2\sqrt{145}}{2}
=-\frac{2\sqrt{145}}{2}
=-\sqrt{145}
$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2\sqrt{145}}{2*1}=\frac{0+2\sqrt{145}}{2}
=\frac{2\sqrt{145}}{2}
=\sqrt{145}
$